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-16x^2+6400=0
a = -16; b = 0; c = +6400;
Δ = b2-4ac
Δ = 02-4·(-16)·6400
Δ = 409600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{409600}=640$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-640}{2*-16}=\frac{-640}{-32} =+20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+640}{2*-16}=\frac{640}{-32} =-20 $
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